E(Y)，D(X)
【正确答案】：
【题目解析】：
Y的边缘分布律：P{Y=0}=P{X=0,Y=0}+P{X=1,Y=0}=0.1+0.2=0.3P{Y=1}=P{X=0,Y=1}+P{X=1,Y=1}=0.1+0.1=0.2P{Y=2}=P{X=0,Y=2}+P{X=1,Y=2}=0.2+0.3=0.5X的边缘分布律：P{X=0}=P{X=0,Y=0}+P{X=0,Y=1}+P{X=0,Y=2}=0.1+0.1+0.2=0.4P{X=1}=P{X=1,Y=0}+P{X=1,Y=1}+P{X=1,Y=2}=0.2+0.1+0.3=0.6
由此可知：E(Y)=1×0.2+2×0.5=1.2；E(X)=E(X²)=0.6方差：D(X)=E(X²)-[E(X)]²=0.24
