用牛顿一莱布尼茨公式计算定积分：∫21(x2)+1/x2dx
2024-07-20高等数学(一)(00020)
用牛顿一莱布尼茨公式计算定积分：
∫21(x2)+1/x2dx
【正确答案】：∫21(x2)+1/x2dx =(1/3x3-1/x)|21 =17/6.
∫21(x2)+1/x2dx
【正确答案】：∫21(x2)+1/x2dx =(1/3x3-1/x)|21 =17/6.
