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计算行列式的值|x+1x||x2x2-x+1|
2024-08-24物流数学(05361)
计算行列式的值
|x+1x|
|x2x2-x+1|
【正确答案】：| x+1 x | |x2 x2-x+1| = | x+1-x x | |x2-(x2-x+1) x2-x+1| = | 1 x | |x-1 x2-x+1| =x2-x+1-x2+x=1
|x+1x|
|x2x2-x+1|
【正确答案】：| x+1 x | |x2 x2-x+1| = | x+1-x x | |x2-(x2-x+1) x2-x+1| = | 1 x | |x-1 x2-x+1| =x2-x+1-x2+x=1
